4(s+2)+s-1=

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Solution for 4(s+2)+s-1= equation:


4(s+2)+s-1=0

We simplify the equation to the form, which is simple to understand 
4(s+2)+s-1=0

Reorder the terms in parentheses
+(+4s+8)+s-1=0

Remove unnecessary parentheses
+4s+8+s-1=0

We move all terms containing s to the left and all other terms to the right. 
+4s+1s=0-8+1

We simplify left and right side of the equation. 
+5s=-7

We divide both sides of the equation by 5 to get s. 
s=-1.4

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