4(s+2)-s=3(s+1)

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Solution for 4(s+2)-s=3(s+1) equation: 


Simplifying
4(s + 2) + -1s = 3(s + 1)

Reorder the terms:
4(2 + s) + -1s = 3(s + 1)
(2 * 4 + s * 4) + -1s = 3(s + 1)
(8 + 4s) + -1s = 3(s + 1)

Combine like terms: 4s + -1s = 3s
8 + 3s = 3(s + 1)

Reorder the terms:
8 + 3s = 3(1 + s)
8 + 3s = (1 * 3 + s * 3)
8 + 3s = (3 + 3s)

Add '-3s' to each side of the equation.
8 + 3s + -3s = 3 + 3s + -3s

Combine like terms: 3s + -3s = 0
8 + 0 = 3 + 3s + -3s
8 = 3 + 3s + -3s

Combine like terms: 3s + -3s = 0
8 = 3 + 0
8 = 3

Solving
8 = 3

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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