4(s+3)+4=2(s-2)+16

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Solution for 4(s+3)+4=2(s-2)+16 equation: 



4(s+3)+4=2(s-2)+16

We move all terms to the left:

4(s+3)+4-(2(s-2)+16)=0

We multiply parentheses

4s-(2(s-2)+16)+12+4=0



We calculate terms in parentheses: -(2(s-2)+16), so:

2(s-2)+16

We multiply parentheses

2s-4+16

We add all the numbers together, and all the variables

2s+12

Back to the equation:

-(2s+12)



We add all the numbers together, and all the variables

4s-(2s+12)+16=0

We get rid of parentheses

4s-2s-12+16=0

We add all the numbers together, and all the variables

2s+4=0

We move all terms containing s to the left, all other terms to the right

2s=-4

s=-4/2

s=-2

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