4(s+3)-1=3(2s+1)+5

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Solution for 4(s+3)-1=3(2s+1)+5 equation: 


Simplifying
4(s + 3) + -1 = 3(2s + 1) + 5

Reorder the terms:
4(3 + s) + -1 = 3(2s + 1) + 5
(3 * 4 + s * 4) + -1 = 3(2s + 1) + 5
(12 + 4s) + -1 = 3(2s + 1) + 5

Reorder the terms:
12 + -1 + 4s = 3(2s + 1) + 5

Combine like terms: 12 + -1 = 11
11 + 4s = 3(2s + 1) + 5

Reorder the terms:
11 + 4s = 3(1 + 2s) + 5
11 + 4s = (1 * 3 + 2s * 3) + 5
11 + 4s = (3 + 6s) + 5

Reorder the terms:
11 + 4s = 3 + 5 + 6s

Combine like terms: 3 + 5 = 8
11 + 4s = 8 + 6s

Solving
11 + 4s = 8 + 6s

Solving for variable 's'.

Move all terms containing s to the left, all other terms to the right.

Add '-6s' to each side of the equation.
11 + 4s + -6s = 8 + 6s + -6s

Combine like terms: 4s + -6s = -2s
11 + -2s = 8 + 6s + -6s

Combine like terms: 6s + -6s = 0
11 + -2s = 8 + 0
11 + -2s = 8

Add '-11' to each side of the equation.
11 + -11 + -2s = 8 + -11

Combine like terms: 11 + -11 = 0
0 + -2s = 8 + -11
-2s = 8 + -11

Combine like terms: 8 + -11 = -3
-2s = -3

Divide each side by '-2'.
s = 1.5

Simplifying
s = 1.5

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