4(s+3)-4=4+8(2-s)

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Solution for 4(s+3)-4=4+8(2-s) equation: 



4(s+3)-4=4+8(2-s)

We move all terms to the left:

4(s+3)-4-(4+8(2-s))=0

We add all the numbers together, and all the variables

4(s+3)-(4+8(-1s+2))-4=0

We multiply parentheses

4s-(4+8(-1s+2))+12-4=0



We calculate terms in parentheses: -(4+8(-1s+2)), so:

4+8(-1s+2)

determiningTheFunctionDomain
8(-1s+2)+4

We multiply parentheses

-8s+16+4

We add all the numbers together, and all the variables

-8s+20

Back to the equation:

-(-8s+20)



We add all the numbers together, and all the variables

4s-(-8s+20)+8=0

We get rid of parentheses

4s+8s-20+8=0

We add all the numbers together, and all the variables

12s-12=0

We move all terms containing s to the left, all other terms to the right

12s=12

s=12/12

s=1

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