4(s-3)+6=6+3s+7

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Solution for 4(s-3)+6=6+3s+7 equation:



4(s-3)+6=6+3s+7
We move all terms to the left:
4(s-3)+6-(6+3s+7)=0
We add all the numbers together, and all the variables
4(s-3)-(3s+13)+6=0
We multiply parentheses
4s-(3s+13)-12+6=0
We get rid of parentheses
4s-3s-13-12+6=0
We add all the numbers together, and all the variables
s-19=0
We move all terms containing s to the left, all other terms to the right
s=19

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