4(s-3)+6=6+3s+7

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Solution for 4(s-3)+6=6+3s+7 equation: 



4(s-3)+6=6+3s+7

We move all terms to the left:

4(s-3)+6-(6+3s+7)=0

We add all the numbers together, and all the variables

4(s-3)-(3s+13)+6=0

We multiply parentheses

4s-(3s+13)-12+6=0

We get rid of parentheses

4s-3s-13-12+6=0

We add all the numbers together, and all the variables

s-19=0

We move all terms containing s to the left, all other terms to the right

s=19

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