4(s-3)=3(s+1)

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Solution for 4(s-3)=3(s+1) equation: 



4(s-3)=3(s+1)

We move all terms to the left:

4(s-3)-(3(s+1))=0

We multiply parentheses

4s-(3(s+1))-12=0



We calculate terms in parentheses: -(3(s+1)), so:

3(s+1)

We multiply parentheses

3s+3

Back to the equation:

-(3s+3)



We get rid of parentheses

4s-3s-3-12=0

We add all the numbers together, and all the variables

s-15=0

We move all terms containing s to the left, all other terms to the right

s=15

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