4(s-4)=2s+12

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Solution for 4(s-4)=2s+12 equation: 



4(s-4)=2s+12

We move all terms to the left:

4(s-4)-(2s+12)=0

We multiply parentheses

4s-(2s+12)-16=0

We get rid of parentheses

4s-2s-12-16=0

We add all the numbers together, and all the variables

2s-28=0

We move all terms containing s to the left, all other terms to the right

2s=28

s=28/2

s=14

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