4(t+1)+3=2(t+5)

Solution for 4(t+1)+3=2(t+5) equation:

4(t+1)+3=2(t+5)

We move all terms to the left:

4(t+1)+3-(2(t+5))=0

We multiply parentheses

4t-(2(t+5))+4+3=0


We calculate terms in parentheses: -(2(t+5)), so:

2(t+5)

We multiply parentheses

2t+10

Back to the equation:

-(2t+10)


We add all the numbers together, and all the variables

4t-(2t+10)+7=0

We get rid of parentheses

4t-2t-10+7=0

We add all the numbers together, and all the variables

2t-3=0

We move all terms containing t to the left, all other terms to the right

2t=3

t=3/2

t=1+1/2