4(t+4)+6=3(t-8)+12

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Solution for 4(t+4)+6=3(t-8)+12 equation: 



4(t+4)+6=3(t-8)+12

We move all terms to the left:

4(t+4)+6-(3(t-8)+12)=0

We multiply parentheses

4t-(3(t-8)+12)+16+6=0



We calculate terms in parentheses: -(3(t-8)+12), so:

3(t-8)+12

We multiply parentheses

3t-24+12

We add all the numbers together, and all the variables

3t-12

Back to the equation:

-(3t-12)



We add all the numbers together, and all the variables

4t-(3t-12)+22=0

We get rid of parentheses

4t-3t+12+22=0

We add all the numbers together, and all the variables

t+34=0

We move all terms containing t to the left, all other terms to the right

t=-34

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