4(t-2)+4t=4(2t+3)-11

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Solution for 4(t-2)+4t=4(2t+3)-11 equation: 


Simplifying
4(t + -2) + 4t = 4(2t + 3) + -11

Reorder the terms:
4(-2 + t) + 4t = 4(2t + 3) + -11
(-2 * 4 + t * 4) + 4t = 4(2t + 3) + -11
(-8 + 4t) + 4t = 4(2t + 3) + -11

Combine like terms: 4t + 4t = 8t
-8 + 8t = 4(2t + 3) + -11

Reorder the terms:
-8 + 8t = 4(3 + 2t) + -11
-8 + 8t = (3 * 4 + 2t * 4) + -11
-8 + 8t = (12 + 8t) + -11

Reorder the terms:
-8 + 8t = 12 + -11 + 8t

Combine like terms: 12 + -11 = 1
-8 + 8t = 1 + 8t

Add '-8t' to each side of the equation.
-8 + 8t + -8t = 1 + 8t + -8t

Combine like terms: 8t + -8t = 0
-8 + 0 = 1 + 8t + -8t
-8 = 1 + 8t + -8t

Combine like terms: 8t + -8t = 0
-8 = 1 + 0
-8 = 1

Solving
-8 = 1

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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