4(t-2)+4t=4(2t+4)-8

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Solution for 4(t-2)+4t=4(2t+4)-8 equation:



4(t-2)+4t=4(2t+4)-8
We move all terms to the left:
4(t-2)+4t-(4(2t+4)-8)=0
We add all the numbers together, and all the variables
4t+4(t-2)-(4(2t+4)-8)=0
We multiply parentheses
4t+4t-(4(2t+4)-8)-8=0
We calculate terms in parentheses: -(4(2t+4)-8), so:
4(2t+4)-8
We multiply parentheses
8t+16-8
We add all the numbers together, and all the variables
8t+8
Back to the equation:
-(8t+8)
We add all the numbers together, and all the variables
8t-(8t+8)-8=0
We get rid of parentheses
8t-8t-8-8=0
We add all the numbers together, and all the variables
-16!=0
There is no solution for this equation

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