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4(t-2)-5(2t-7)=25-7(5t+2)
We move all terms to the left:
4(t-2)-5(2t-7)-(25-7(5t+2))=0
We multiply parentheses
4t-10t-(25-7(5t+2))-8+35=0
We calculate terms in parentheses: -(25-7(5t+2)), so:We add all the numbers together, and all the variables
25-7(5t+2)
determiningTheFunctionDomain -7(5t+2)+25
We multiply parentheses
-35t-14+25
We add all the numbers together, and all the variables
-35t+11
Back to the equation:
-(-35t+11)
-6t-(-35t+11)+27=0
We get rid of parentheses
-6t+35t-11+27=0
We add all the numbers together, and all the variables
29t+16=0
We move all terms containing t to the left, all other terms to the right
29t=-16
t=-16/29
t=-16/29
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