4(t-2)-5(2t-7)=25-7(5t+2)

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Solution for 4(t-2)-5(2t-7)=25-7(5t+2) equation: 



4(t-2)-5(2t-7)=25-7(5t+2)

We move all terms to the left:

4(t-2)-5(2t-7)-(25-7(5t+2))=0

We multiply parentheses

4t-10t-(25-7(5t+2))-8+35=0



We calculate terms in parentheses: -(25-7(5t+2)), so:

25-7(5t+2)

determiningTheFunctionDomain
-7(5t+2)+25

We multiply parentheses

-35t-14+25

We add all the numbers together, and all the variables

-35t+11

Back to the equation:

-(-35t+11)



We add all the numbers together, and all the variables

-6t-(-35t+11)+27=0

We get rid of parentheses

-6t+35t-11+27=0

We add all the numbers together, and all the variables

29t+16=0

We move all terms containing t to the left, all other terms to the right

29t=-16

t=-16/29

t=-16/29

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