4(t-3)+12=-4t

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Solution for 4(t-3)+12=-4t equation: 



4(t-3)+12=-4t

We move all terms to the left:

4(t-3)+12-(-4t)=0

We multiply parentheses

4t-(-4t)-12+12=0

We get rid of parentheses

4t+4t-12+12=0

We add all the numbers together, and all the variables

8t=0

t=0/8

t=0

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