4(t-3)+4=(2t-6)

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Solution for 4(t-3)+4=(2t-6) equation:



4(t-3)+4=(2t-6)
We move all terms to the left:
4(t-3)+4-((2t-6))=0
We multiply parentheses
4t-((2t-6))-12+4=0
We calculate terms in parentheses: -((2t-6)), so:
(2t-6)
We get rid of parentheses
2t-6
Back to the equation:
-(2t-6)
We add all the numbers together, and all the variables
4t-(2t-6)-8=0
We get rid of parentheses
4t-2t+6-8=0
We add all the numbers together, and all the variables
2t-2=0
We move all terms containing t to the left, all other terms to the right
2t=2
t=2/2
t=1

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