4(t-3)+8=4(2t-5)

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Solution for 4(t-3)+8=4(2t-5) equation: 



4(t-3)+8=4(2t-5)

We move all terms to the left:

4(t-3)+8-(4(2t-5))=0

We multiply parentheses

4t-(4(2t-5))-12+8=0



We calculate terms in parentheses: -(4(2t-5)), so:

4(2t-5)

We multiply parentheses

8t-20

Back to the equation:

-(8t-20)



We add all the numbers together, and all the variables

4t-(8t-20)-4=0

We get rid of parentheses

4t-8t+20-4=0

We add all the numbers together, and all the variables

-4t+16=0

We move all terms containing t to the left, all other terms to the right

-4t=-16

t=-16/-4

t=+4

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