4(t-3)=5(2t+3)

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Solution for 4(t-3)=5(2t+3) equation: 



4(t-3)=5(2t+3)

We move all terms to the left:

4(t-3)-(5(2t+3))=0

We multiply parentheses

4t-(5(2t+3))-12=0



We calculate terms in parentheses: -(5(2t+3)), so:

5(2t+3)

We multiply parentheses

10t+15

Back to the equation:

-(10t+15)



We get rid of parentheses

4t-10t-15-12=0

We add all the numbers together, and all the variables

-6t-27=0

We move all terms containing t to the left, all other terms to the right

-6t=27

t=27/-6

t=-4+1/2

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