4(t-4)+2=3(t+1)

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Solution for 4(t-4)+2=3(t+1) equation: 



4(t-4)+2=3(t+1)

We move all terms to the left:

4(t-4)+2-(3(t+1))=0

We multiply parentheses

4t-(3(t+1))-16+2=0



We calculate terms in parentheses: -(3(t+1)), so:

3(t+1)

We multiply parentheses

3t+3

Back to the equation:

-(3t+3)



We add all the numbers together, and all the variables

4t-(3t+3)-14=0

We get rid of parentheses

4t-3t-3-14=0

We add all the numbers together, and all the variables

t-17=0

We move all terms containing t to the left, all other terms to the right

t=17

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