4(t-4)+4t=4(2t+3)-10

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Solution for 4(t-4)+4t=4(2t+3)-10 equation:


Simplifying
4(t + -4) + 4t = 4(2t + 3) + -10

Reorder the terms:
4(-4 + t) + 4t = 4(2t + 3) + -10
(-4 * 4 + t * 4) + 4t = 4(2t + 3) + -10
(-16 + 4t) + 4t = 4(2t + 3) + -10

Combine like terms: 4t + 4t = 8t
-16 + 8t = 4(2t + 3) + -10

Reorder the terms:
-16 + 8t = 4(3 + 2t) + -10
-16 + 8t = (3 * 4 + 2t * 4) + -10
-16 + 8t = (12 + 8t) + -10

Reorder the terms:
-16 + 8t = 12 + -10 + 8t

Combine like terms: 12 + -10 = 2
-16 + 8t = 2 + 8t

Add '-8t' to each side of the equation.
-16 + 8t + -8t = 2 + 8t + -8t

Combine like terms: 8t + -8t = 0
-16 + 0 = 2 + 8t + -8t
-16 = 2 + 8t + -8t

Combine like terms: 8t + -8t = 0
-16 = 2 + 0
-16 = 2

Solving
-16 = 2

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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