4(t-4)-3(2t-5)=4-7(3t+1)

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Solution for 4(t-4)-3(2t-5)=4-7(3t+1) equation: 



4(t-4)-3(2t-5)=4-7(3t+1)

We move all terms to the left:

4(t-4)-3(2t-5)-(4-7(3t+1))=0

We multiply parentheses

4t-6t-(4-7(3t+1))-16+15=0



We calculate terms in parentheses: -(4-7(3t+1)), so:

4-7(3t+1)

determiningTheFunctionDomain
-7(3t+1)+4

We multiply parentheses

-21t-7+4

We add all the numbers together, and all the variables

-21t-3

Back to the equation:

-(-21t-3)



We add all the numbers together, and all the variables

-2t-(-21t-3)-1=0

We get rid of parentheses

-2t+21t+3-1=0

We add all the numbers together, and all the variables

19t+2=0

We move all terms containing t to the left, all other terms to the right

19t=-2

t=-2/19

t=-2/19

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