4(t-5)=5(2t+2)

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Solution for 4(t-5)=5(2t+2) equation: 



4(t-5)=5(2t+2)

We move all terms to the left:

4(t-5)-(5(2t+2))=0

We multiply parentheses

4t-(5(2t+2))-20=0



We calculate terms in parentheses: -(5(2t+2)), so:

5(2t+2)

We multiply parentheses

10t+10

Back to the equation:

-(10t+10)



We get rid of parentheses

4t-10t-10-20=0

We add all the numbers together, and all the variables

-6t-30=0

We move all terms containing t to the left, all other terms to the right

-6t=30

t=30/-6

t=-5

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