4(t-6)+8t=6(2t+2)-11

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Solution for 4(t-6)+8t=6(2t+2)-11 equation:



4(t-6)+8t=6(2t+2)-11
We move all terms to the left:
4(t-6)+8t-(6(2t+2)-11)=0
We add all the numbers together, and all the variables
8t+4(t-6)-(6(2t+2)-11)=0
We multiply parentheses
8t+4t-(6(2t+2)-11)-24=0
We calculate terms in parentheses: -(6(2t+2)-11), so:
6(2t+2)-11
We multiply parentheses
12t+12-11
We add all the numbers together, and all the variables
12t+1
Back to the equation:
-(12t+1)
We add all the numbers together, and all the variables
12t-(12t+1)-24=0
We get rid of parentheses
12t-12t-1-24=0
We add all the numbers together, and all the variables
-25!=0
There is no solution for this equation

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