4(t-7)=3(2t+1)

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Solution for 4(t-7)=3(2t+1) equation: 



4(t-7)=3(2t+1)

We move all terms to the left:

4(t-7)-(3(2t+1))=0

We multiply parentheses

4t-(3(2t+1))-28=0



We calculate terms in parentheses: -(3(2t+1)), so:

3(2t+1)

We multiply parentheses

6t+3

Back to the equation:

-(6t+3)



We get rid of parentheses

4t-6t-3-28=0

We add all the numbers together, and all the variables

-2t-31=0

We move all terms containing t to the left, all other terms to the right

-2t=31

t=31/-2

t=-15+1/2

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