4(u+)+u=3(u-2)+2

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Solution for 4(u+)+u=3(u-2)+2 equation: 



4(u+)+u=3(u-2)+2

We move all terms to the left:

4(u+)+u-(3(u-2)+2)=0

We add all the numbers together, and all the variables

4(+u)+u-(3(u-2)+2)=0

We add all the numbers together, and all the variables

u+4(+u)-(3(u-2)+2)=0

We multiply parentheses

u+4u-(3(u-2)+2)=0



We calculate terms in parentheses: -(3(u-2)+2), so:

3(u-2)+2

We multiply parentheses

3u-6+2

We add all the numbers together, and all the variables

3u-4

Back to the equation:

-(3u-4)



We add all the numbers together, and all the variables

5u-(3u-4)=0

We get rid of parentheses

5u-3u+4=0

We add all the numbers together, and all the variables

2u+4=0

We move all terms containing u to the left, all other terms to the right

2u=-4

u=-4/2

u=-2

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