4(u+1)+5=6(u+1)+u

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Solution for 4(u+1)+5=6(u+1)+u equation: 



4(u+1)+5=6(u+1)+u

We move all terms to the left:

4(u+1)+5-(6(u+1)+u)=0

We multiply parentheses

4u-(6(u+1)+u)+4+5=0



We calculate terms in parentheses: -(6(u+1)+u), so:

6(u+1)+u

We add all the numbers together, and all the variables

u+6(u+1)

We multiply parentheses

u+6u+6

We add all the numbers together, and all the variables

7u+6

Back to the equation:

-(7u+6)



We add all the numbers together, and all the variables

4u-(7u+6)+9=0

We get rid of parentheses

4u-7u-6+9=0

We add all the numbers together, and all the variables

-3u+3=0

We move all terms containing u to the left, all other terms to the right

-3u=-3

u=-3/-3

u=1

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