4(u+1)+6u=2(u+2)-8

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Solution for 4(u+1)+6u=2(u+2)-8 equation: 



4(u+1)+6u=2(u+2)-8

We move all terms to the left:

4(u+1)+6u-(2(u+2)-8)=0

We add all the numbers together, and all the variables

6u+4(u+1)-(2(u+2)-8)=0

We multiply parentheses

6u+4u-(2(u+2)-8)+4=0



We calculate terms in parentheses: -(2(u+2)-8), so:

2(u+2)-8

We multiply parentheses

2u+4-8

We add all the numbers together, and all the variables

2u-4

Back to the equation:

-(2u-4)



We add all the numbers together, and all the variables

10u-(2u-4)+4=0

We get rid of parentheses

10u-2u+4+4=0

We add all the numbers together, and all the variables

8u+8=0

We move all terms containing u to the left, all other terms to the right

8u=-8

u=-8/8

u=-1

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