4(u+1)+u=5(u-1)+9

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Solution for 4(u+1)+u=5(u-1)+9 equation: 


Simplifying
4(u + 1) + u = 5(u + -1) + 9

Reorder the terms:
4(1 + u) + u = 5(u + -1) + 9
(1 * 4 + u * 4) + u = 5(u + -1) + 9
(4 + 4u) + u = 5(u + -1) + 9

Combine like terms: 4u + u = 5u
4 + 5u = 5(u + -1) + 9

Reorder the terms:
4 + 5u = 5(-1 + u) + 9
4 + 5u = (-1 * 5 + u * 5) + 9
4 + 5u = (-5 + 5u) + 9

Reorder the terms:
4 + 5u = -5 + 9 + 5u

Combine like terms: -5 + 9 = 4
4 + 5u = 4 + 5u

Add '-4' to each side of the equation.
4 + -4 + 5u = 4 + -4 + 5u

Combine like terms: 4 + -4 = 0
0 + 5u = 4 + -4 + 5u
5u = 4 + -4 + 5u

Combine like terms: 4 + -4 = 0
5u = 0 + 5u
5u = 5u

Add '-5u' to each side of the equation.
5u + -5u = 5u + -5u

Combine like terms: 5u + -5u = 0
0 = 5u + -5u

Combine like terms: 5u + -5u = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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