4(u+1)-7=3(u-1)+u

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Solution for 4(u+1)-7=3(u-1)+u equation:


Simplifying
4(u + 1) + -7 = 3(u + -1) + u

Reorder the terms:
4(1 + u) + -7 = 3(u + -1) + u
(1 * 4 + u * 4) + -7 = 3(u + -1) + u
(4 + 4u) + -7 = 3(u + -1) + u

Reorder the terms:
4 + -7 + 4u = 3(u + -1) + u

Combine like terms: 4 + -7 = -3
-3 + 4u = 3(u + -1) + u

Reorder the terms:
-3 + 4u = 3(-1 + u) + u
-3 + 4u = (-1 * 3 + u * 3) + u
-3 + 4u = (-3 + 3u) + u

Combine like terms: 3u + u = 4u
-3 + 4u = -3 + 4u

Add '3' to each side of the equation.
-3 + 3 + 4u = -3 + 3 + 4u

Combine like terms: -3 + 3 = 0
0 + 4u = -3 + 3 + 4u
4u = -3 + 3 + 4u

Combine like terms: -3 + 3 = 0
4u = 0 + 4u
4u = 4u

Add '-4u' to each side of the equation.
4u + -4u = 4u + -4u

Combine like terms: 4u + -4u = 0
0 = 4u + -4u

Combine like terms: 4u + -4u = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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