4(u+1)-u=3(u-1)+7

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Solution for 4(u+1)-u=3(u-1)+7 equation: 


Simplifying
4(u + 1) + -1u = 3(u + -1) + 7

Reorder the terms:
4(1 + u) + -1u = 3(u + -1) + 7
(1 * 4 + u * 4) + -1u = 3(u + -1) + 7
(4 + 4u) + -1u = 3(u + -1) + 7

Combine like terms: 4u + -1u = 3u
4 + 3u = 3(u + -1) + 7

Reorder the terms:
4 + 3u = 3(-1 + u) + 7
4 + 3u = (-1 * 3 + u * 3) + 7
4 + 3u = (-3 + 3u) + 7

Reorder the terms:
4 + 3u = -3 + 7 + 3u

Combine like terms: -3 + 7 = 4
4 + 3u = 4 + 3u

Add '-4' to each side of the equation.
4 + -4 + 3u = 4 + -4 + 3u

Combine like terms: 4 + -4 = 0
0 + 3u = 4 + -4 + 3u
3u = 4 + -4 + 3u

Combine like terms: 4 + -4 = 0
3u = 0 + 3u
3u = 3u

Add '-3u' to each side of the equation.
3u + -3u = 3u + -3u

Combine like terms: 3u + -3u = 0
0 = 3u + -3u

Combine like terms: 3u + -3u = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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