4(u+2)+u=2(u-1)+9

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Solution for 4(u+2)+u=2(u-1)+9 equation:



4(u+2)+u=2(u-1)+9
We move all terms to the left:
4(u+2)+u-(2(u-1)+9)=0
We add all the numbers together, and all the variables
u+4(u+2)-(2(u-1)+9)=0
We multiply parentheses
u+4u-(2(u-1)+9)+8=0
We calculate terms in parentheses: -(2(u-1)+9), so:
2(u-1)+9
We multiply parentheses
2u-2+9
We add all the numbers together, and all the variables
2u+7
Back to the equation:
-(2u+7)
We add all the numbers together, and all the variables
5u-(2u+7)+8=0
We get rid of parentheses
5u-2u-7+8=0
We add all the numbers together, and all the variables
3u+1=0
We move all terms containing u to the left, all other terms to the right
3u=-1
u=-1/3
u=-1/3

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