4(u+2)-7u=35

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Solution for 4(u+2)-7u=35 equation: 



4(u+2)-7u=35

We move all terms to the left:

4(u+2)-7u-(35)=0

We add all the numbers together, and all the variables

-7u+4(u+2)-35=0

We multiply parentheses

-7u+4u+8-35=0

We add all the numbers together, and all the variables

-3u-27=0

We move all terms containing u to the left, all other terms to the right

-3u=27

u=27/-3

u=-9

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