4(u+2)-u=2(u-1)=9

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Solution for 4(u+2)-u=2(u-1)=9 equation: 



4(u+2)-u=2(u-1)=9

We move all terms to the left:

4(u+2)-u-(2(u-1))=0

We add all the numbers together, and all the variables

-1u+4(u+2)-(2(u-1))=0

We multiply parentheses

-1u+4u-(2(u-1))+8=0



We calculate terms in parentheses: -(2(u-1)), so:

2(u-1)

We multiply parentheses

2u-2

Back to the equation:

-(2u-2)



We add all the numbers together, and all the variables

3u-(2u-2)+8=0

We get rid of parentheses

3u-2u+2+8=0

We add all the numbers together, and all the variables

u+10=0

We move all terms containing u to the left, all other terms to the right

u=-10

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