4(u+2)=-2(3u-3)+4u

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Solution for 4(u+2)=-2(3u-3)+4u equation: 



4(u+2)=-2(3u-3)+4u

We move all terms to the left:

4(u+2)-(-2(3u-3)+4u)=0

We multiply parentheses

4u-(-2(3u-3)+4u)+8=0



We calculate terms in parentheses: -(-2(3u-3)+4u), so:

-2(3u-3)+4u

We add all the numbers together, and all the variables

4u-2(3u-3)

We multiply parentheses

4u-6u+6

We add all the numbers together, and all the variables

-2u+6

Back to the equation:

-(-2u+6)



We get rid of parentheses

4u+2u-6+8=0

We add all the numbers together, and all the variables

6u+2=0

We move all terms containing u to the left, all other terms to the right

6u=-2

u=-2/6

u=-1/3

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