4(u+2)=-3(4u-2)+6u

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Solution for 4(u+2)=-3(4u-2)+6u equation: 



4(u+2)=-3(4u-2)+6u

We move all terms to the left:

4(u+2)-(-3(4u-2)+6u)=0

We multiply parentheses

4u-(-3(4u-2)+6u)+8=0



We calculate terms in parentheses: -(-3(4u-2)+6u), so:

-3(4u-2)+6u

We add all the numbers together, and all the variables

6u-3(4u-2)

We multiply parentheses

6u-12u+6

We add all the numbers together, and all the variables

-6u+6

Back to the equation:

-(-6u+6)



We get rid of parentheses

4u+6u-6+8=0

We add all the numbers together, and all the variables

10u+2=0

We move all terms containing u to the left, all other terms to the right

10u=-2

u=-2/10

u=-1/5

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