4(u+3)=-2(5u-4)+6

Solution for 4(u+3)=-2(5u-4)+6 equation:

4(u+3)=-2(5u-4)+6

We move all terms to the left:

4(u+3)-(-2(5u-4)+6)=0

We multiply parentheses

4u-(-2(5u-4)+6)+12=0


We calculate terms in parentheses: -(-2(5u-4)+6), so:

-2(5u-4)+6

We multiply parentheses

-10u+8+6

We add all the numbers together, and all the variables

-10u+14

Back to the equation:

-(-10u+14)


We get rid of parentheses

4u+10u-14+12=0

We add all the numbers together, and all the variables

14u-2=0

We move all terms containing u to the left, all other terms to the right

14u=2

u=2/14

u=1/7