4(u+3)=-3(3u-2)+9u

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Solution for 4(u+3)=-3(3u-2)+9u equation: 



4(u+3)=-3(3u-2)+9u

We move all terms to the left:

4(u+3)-(-3(3u-2)+9u)=0

We multiply parentheses

4u-(-3(3u-2)+9u)+12=0



We calculate terms in parentheses: -(-3(3u-2)+9u), so:

-3(3u-2)+9u

We add all the numbers together, and all the variables

9u-3(3u-2)

We multiply parentheses

9u-9u+6

We add all the numbers together, and all the variables

6

Back to the equation:

-(6)



We add all the numbers together, and all the variables

4u+6=0

We move all terms containing u to the left, all other terms to the right

4u=-6

u=-6/4

u=-1+1/2

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