4(u+3)=-3(4u-2)+2u

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Solution for 4(u+3)=-3(4u-2)+2u equation:



4(u+3)=-3(4u-2)+2u
We move all terms to the left:
4(u+3)-(-3(4u-2)+2u)=0
We multiply parentheses
4u-(-3(4u-2)+2u)+12=0
We calculate terms in parentheses: -(-3(4u-2)+2u), so:
-3(4u-2)+2u
We add all the numbers together, and all the variables
2u-3(4u-2)
We multiply parentheses
2u-12u+6
We add all the numbers together, and all the variables
-10u+6
Back to the equation:
-(-10u+6)
We get rid of parentheses
4u+10u-6+12=0
We add all the numbers together, and all the variables
14u+6=0
We move all terms containing u to the left, all other terms to the right
14u=-6
u=-6/14
u=-3/7

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