4(u+3)=-4(4u-1)+8u

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Solution for 4(u+3)=-4(4u-1)+8u equation: 



4(u+3)=-4(4u-1)+8u

We move all terms to the left:

4(u+3)-(-4(4u-1)+8u)=0

We multiply parentheses

4u-(-4(4u-1)+8u)+12=0



We calculate terms in parentheses: -(-4(4u-1)+8u), so:

-4(4u-1)+8u

We add all the numbers together, and all the variables

8u-4(4u-1)

We multiply parentheses

8u-16u+4

We add all the numbers together, and all the variables

-8u+4

Back to the equation:

-(-8u+4)



We get rid of parentheses

4u+8u-4+12=0

We add all the numbers together, and all the variables

12u+8=0

We move all terms containing u to the left, all other terms to the right

12u=-8

u=-8/12

u=-2/3

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