4(u+3)=6u+6

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Solution for 4(u+3)=6u+6 equation: 



4(u+3)=6u+6

We move all terms to the left:

4(u+3)-(6u+6)=0

We multiply parentheses

4u-(6u+6)+12=0

We get rid of parentheses

4u-6u-6+12=0

We add all the numbers together, and all the variables

-2u+6=0

We move all terms containing u to the left, all other terms to the right

-2u=-6

u=-6/-2

u=+3

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