4(u+3)=7u-18

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Solution for 4(u+3)=7u-18 equation: 



4(u+3)=7u-18

We move all terms to the left:

4(u+3)-(7u-18)=0

We multiply parentheses

4u-(7u-18)+12=0

We get rid of parentheses

4u-7u+18+12=0

We add all the numbers together, and all the variables

-3u+30=0

We move all terms containing u to the left, all other terms to the right

-3u=-30

u=-30/-3

u=+10

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