4(u+4)=-3(4u-4)+8u

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Solution for 4(u+4)=-3(4u-4)+8u equation: 



4(u+4)=-3(4u-4)+8u

We move all terms to the left:

4(u+4)-(-3(4u-4)+8u)=0

We multiply parentheses

4u-(-3(4u-4)+8u)+16=0



We calculate terms in parentheses: -(-3(4u-4)+8u), so:

-3(4u-4)+8u

We add all the numbers together, and all the variables

8u-3(4u-4)

We multiply parentheses

8u-12u+12

We add all the numbers together, and all the variables

-4u+12

Back to the equation:

-(-4u+12)



We get rid of parentheses

4u+4u-12+16=0

We add all the numbers together, and all the variables

8u+4=0

We move all terms containing u to the left, all other terms to the right

8u=-4

u=-4/8

u=-1/2

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