4(u+5)=-3(3u-4)+u

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Solution for 4(u+5)=-3(3u-4)+u equation: 



4(u+5)=-3(3u-4)+u

We move all terms to the left:

4(u+5)-(-3(3u-4)+u)=0

We multiply parentheses

4u-(-3(3u-4)+u)+20=0



We calculate terms in parentheses: -(-3(3u-4)+u), so:

-3(3u-4)+u

We add all the numbers together, and all the variables

u-3(3u-4)

We multiply parentheses

u-9u+12

We add all the numbers together, and all the variables

-8u+12

Back to the equation:

-(-8u+12)



We get rid of parentheses

4u+8u-12+20=0

We add all the numbers together, and all the variables

12u+8=0

We move all terms containing u to the left, all other terms to the right

12u=-8

u=-8/12

u=-2/3

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