4(u-2)-6=-4(-6u+3)-4u

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Solution for 4(u-2)-6=-4(-6u+3)-4u equation: 



4(u-2)-6=-4(-6u+3)-4u

We move all terms to the left:

4(u-2)-6-(-4(-6u+3)-4u)=0

We multiply parentheses

4u-(-4(-6u+3)-4u)-8-6=0



We calculate terms in parentheses: -(-4(-6u+3)-4u), so:

-4(-6u+3)-4u

We add all the numbers together, and all the variables

-4u-4(-6u+3)

We multiply parentheses

-4u+24u-12

We add all the numbers together, and all the variables

20u-12

Back to the equation:

-(20u-12)



We add all the numbers together, and all the variables

4u-(20u-12)-14=0

We get rid of parentheses

4u-20u+12-14=0

We add all the numbers together, and all the variables

-16u-2=0

We move all terms containing u to the left, all other terms to the right

-16u=2

u=2/-16

u=-1/8

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