4(u-2)=5u+5-2(-4u-1)

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Solution for 4(u-2)=5u+5-2(-4u-1) equation: 



4(u-2)=5u+5-2(-4u-1)

We move all terms to the left:

4(u-2)-(5u+5-2(-4u-1))=0

We multiply parentheses

4u-(5u+5-2(-4u-1))-8=0



We calculate terms in parentheses: -(5u+5-2(-4u-1)), so:

5u+5-2(-4u-1)

determiningTheFunctionDomain
5u-2(-4u-1)+5

We multiply parentheses

5u+8u+2+5

We add all the numbers together, and all the variables

13u+7

Back to the equation:

-(13u+7)



We get rid of parentheses

4u-13u-7-8=0

We add all the numbers together, and all the variables

-9u-15=0

We move all terms containing u to the left, all other terms to the right

-9u=15

u=15/-9

u=-1+2/3

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