4(u-3)-1=-3(-5u+5)-3u

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Solution for 4(u-3)-1=-3(-5u+5)-3u equation: 



4(u-3)-1=-3(-5u+5)-3u

We move all terms to the left:

4(u-3)-1-(-3(-5u+5)-3u)=0

We multiply parentheses

4u-(-3(-5u+5)-3u)-12-1=0



We calculate terms in parentheses: -(-3(-5u+5)-3u), so:

-3(-5u+5)-3u

We add all the numbers together, and all the variables

-3u-3(-5u+5)

We multiply parentheses

-3u+15u-15

We add all the numbers together, and all the variables

12u-15

Back to the equation:

-(12u-15)



We add all the numbers together, and all the variables

4u-(12u-15)-13=0

We get rid of parentheses

4u-12u+15-13=0

We add all the numbers together, and all the variables

-8u+2=0

We move all terms containing u to the left, all other terms to the right

-8u=-2

u=-2/-8

u=1/4

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