4(u-3)-4=-3(-7u+4)-5u

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Solution for 4(u-3)-4=-3(-7u+4)-5u equation: 



4(u-3)-4=-3(-7u+4)-5u

We move all terms to the left:

4(u-3)-4-(-3(-7u+4)-5u)=0

We multiply parentheses

4u-(-3(-7u+4)-5u)-12-4=0



We calculate terms in parentheses: -(-3(-7u+4)-5u), so:

-3(-7u+4)-5u

We add all the numbers together, and all the variables

-5u-3(-7u+4)

We multiply parentheses

-5u+21u-12

We add all the numbers together, and all the variables

16u-12

Back to the equation:

-(16u-12)



We add all the numbers together, and all the variables

4u-(16u-12)-16=0

We get rid of parentheses

4u-16u+12-16=0

We add all the numbers together, and all the variables

-12u-4=0

We move all terms containing u to the left, all other terms to the right

-12u=4

u=4/-12

u=-1/3

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