4(u-3)=6u+2-2(-5u-2)

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Solution for 4(u-3)=6u+2-2(-5u-2) equation: 



4(u-3)=6u+2-2(-5u-2)

We move all terms to the left:

4(u-3)-(6u+2-2(-5u-2))=0

We multiply parentheses

4u-(6u+2-2(-5u-2))-12=0



We calculate terms in parentheses: -(6u+2-2(-5u-2)), so:

6u+2-2(-5u-2)

determiningTheFunctionDomain
6u-2(-5u-2)+2

We multiply parentheses

6u+10u+4+2

We add all the numbers together, and all the variables

16u+6

Back to the equation:

-(16u+6)



We get rid of parentheses

4u-16u-6-12=0

We add all the numbers together, and all the variables

-12u-18=0

We move all terms containing u to the left, all other terms to the right

-12u=18

u=18/-12

u=-1+1/2

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