4(u-3)=8u+2-2(-5u-2)

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Solution for 4(u-3)=8u+2-2(-5u-2) equation: 



4(u-3)=8u+2-2(-5u-2)

We move all terms to the left:

4(u-3)-(8u+2-2(-5u-2))=0

We multiply parentheses

4u-(8u+2-2(-5u-2))-12=0



We calculate terms in parentheses: -(8u+2-2(-5u-2)), so:

8u+2-2(-5u-2)

determiningTheFunctionDomain
8u-2(-5u-2)+2

We multiply parentheses

8u+10u+4+2

We add all the numbers together, and all the variables

18u+6

Back to the equation:

-(18u+6)



We get rid of parentheses

4u-18u-6-12=0

We add all the numbers together, and all the variables

-14u-18=0

We move all terms containing u to the left, all other terms to the right

-14u=18

u=18/-14

u=-1+2/7

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