4(u-4)=8u+12

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Solution for 4(u-4)=8u+12 equation:



4(u-4)=8u+12
We move all terms to the left:
4(u-4)-(8u+12)=0
We multiply parentheses
4u-(8u+12)-16=0
We get rid of parentheses
4u-8u-12-16=0
We add all the numbers together, and all the variables
-4u-28=0
We move all terms containing u to the left, all other terms to the right
-4u=28
u=28/-4
u=-7

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