4(u-6)=2u-32

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Solution for 4(u-6)=2u-32 equation: 



4(u-6)=2u-32

We move all terms to the left:

4(u-6)-(2u-32)=0

We multiply parentheses

4u-(2u-32)-24=0

We get rid of parentheses

4u-2u+32-24=0

We add all the numbers together, and all the variables

2u+8=0

We move all terms containing u to the left, all other terms to the right

2u=-8

u=-8/2

u=-4

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